Q. Write a single 8086 assembly instruction to execute the following: 1. Toggle the logic level of even bits in the Accumulator Register. 2. Swap the contents of DX with the contents of memory location [(DS)0+(BX)+(DI)+3FFFh]. 3. Find the squares of BL and save the result in AX, when (AL)=(BL). 4. Subtract the word content of the storage location pointed by base-indexed addressing mode [BX]+[SI] from the register AX. 5. Call a far-process subroutine, if the physical address of the subroutine is 11002h in CS=1100h. 6. Divide the signed number in register DX by 16, when CL=4. 7. Save the status flags in stack memory. 8. Load the BX and ES registers from the address [AB00h] and address [AB02h] respectively. 9. Move the content of the low nibble of AH to high nibble and clear the low nibble, when CL=4. 10. Jump to code memory location LABEL when the (CX) #0 or (ZF)=1