Q1. For refrigerant 134a, determine the values specified for each of the following conditions: p =...

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Q1. For refrigerant 134a, determine the values specified for each of the following conditions: p = 140 lb/in p = 20 lb/in P = 200 psi P = u = 134.09 BTU/lb T = 75F v = 0.1865 ft/lb 150 psi T = BTU/lb v= BTU/lb h = T = 190F ft/lb h = Answer: Hint: for 4th line interpolate one side then the other. In numerical order, the values you should get are: 0.4066, 0.4666, 2.7281, 97.90, 104.80, 107.11, 138.28, 220.00. u = u = F|V= V = ft/lb ft/lb BTU/lb BTU/lb Q1. For refrigerant 134a, determine the values specified for each of the following conditions: p = 140 lb/in p = 20 lb/in P = 200 psi P = u = 134.09 BTU/lb T = 75F v = 0.1865 ft/lb 150 psi T = BTU/lb v= BTU/lb h = T = 190F ft/lb h = Answer: Hint: for 4th line interpolate one side then the other. In numerical order, the values you should get are: 0.4066, 0.4666, 2.7281, 97.90, 104.80, 107.11, 138.28, 220.00. u = u = F|V= V = ft/lb ft/lb BTU/lb BTU/lb

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Since I cannot directly access refrigerant property tables or perform complex interpolations without specific data input I can guide you on how to find the values for refrigerant R134a under the condi... View the full answer