Question: Q14. It is a standard normal distribution. Find Ps, the 5th percentile. This is the bone density score separating the bottom 5% from the

Q14. It is a standard normal distribution. Find Ps, the 5th percentile.

Q14. It is a standard normal distribution. Find Ps, the 5th percentile. This is the bone density score separating the bottom 5% from the top 95%. Q15. It is a standard normal distribution. If bone density scores in the bottom 2% and the top 2% are used as cutoff points for levels that are too low or too high, find the two readings that are cutoff values. Q16. Find the critical value. Z0.01 Q17. Find the critical value. Z0.04 3 6.2 Real Applications of Normal Distribution For each question, please draw a density curve with the given information. Also, find the corresponding value for the z score in the graph. Q1-Q4. Seat Designs Sitting Back-to-Knee Length (inches) Mean St. Dev. Males Females 23.5 1.1 in Distribution Normal 22.7 1.0 in Normal Q1. Find the probability that a male has a back-to-knee length less than 21 in. Find the z score for 21 in. Q2. Find the probability that a female has a back-to-knee length greater than 24.0 in. Find the z score for 24.0 in. Q3. Find the probability that a female has a back-to-knee length between 22.0 in. and 24.0 in. Find the z scores for 22.0 in and 24.0 in. Q4. For males, find P90, which is the length separating the bottom 90% from the top 10%.

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