Q2. Let Y be the marks in EC003, X, is a random vector of gender and X2 is a random vect of section. Answer the following: (a) X1 (b) X2 (c) X1 and X2 (d) Y. (2+4 mar (i) E [E [Y\X1, X2]\\X1] is a function of......... (ii) Find E [E [Y\X1, X2] \X] using Table 1 and Table 2. Table 1: Number of students by gender and section Male Female Third Gender Section A 39 50 1 90 Section B 50 55 5 110 Total Table 2: Mean marks by gender and section Male Female Third Gender 777 Section A Section B 70 80 75 85 80 78