Question: Q4. Write a function named 'printEvens' that accepts 2 integers 'a' and 'b' and creates and returns an array such that all numbers between a

Q4. Write a function named 'printEvens' that accepts 2 integers 'a' and 'b' and

creates and returns an array such that all numbers between a and b (inclusive) contain

only even digits (0 is considered even)!

For example, printEvens(433, 452) would create and return a new list with the following

values: [440, 442, 444, 446, 448]

NOTE: EACH and EVERY digit MUST be an EVEN number, NOT simply that the entire

number itself be EVEN!

import math

import random

import string

import collections

import datetime

import re

import time

import copy

# YOUR CODE BELOW...

def checkRegex(str2) :

your code here...

# end def

def fancyList(table, cityFrom, cityTo) :

your code here...

# end def

def natureSequence(fn, sn, n) :

your code here...

# end def

def printEvens(a, b) :

your code here...

# end def

def generatePokerHand(deck, coords) :

your code here...

# end def

def main( ) :

rv = checkRegex("abcdefghijklmnopqrstuvwxyz")

print(rv)

rv = checkRegex("Mariner!")

print(rv)

rv = checkRegex("acdefGhij*012345")

print(rv)

fancyList( )

rv = natureSequence(0, 1, 10)

rv = natureSequence(1, 3, 15)

printEvens(433, 452)

printEvens(2048, 2188)

deck = [["2C", "3C", "4C", "5C", "6C", "7C", "8C", "9C", "XC", "JC", "QC", "KC","AC"],

["2D", "3D", "4D", "5D", "6D", "7D", "8D", "9D", "XD", "JD", "QD", "KD", "AD"],

["2H", "3H", "4H", "5H", "6H", "7H", "8H", "9H", "XH", "JH", "QH", "KH", "AH"],

["2S", "3S", "4S", "5S", "6S", "7S", "8S", "9S", "XS", "JS", "QS", "KS", "AS"]

]

coords=["22", "0A", "38", "1B", "25"]

rv = generatePokerHand(deck, coords)

coords=["23", "24", "25", "26", "27"]

rv = generatePokerHand(deck, coords)

# end main( )

if __name__ == "__main__" :

main( )

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