Write a function named 'printEvens' that accepts 2 integers 'a' and 'b' and creates and returns an array such that all numbers between a and b (inclusive) contain only even digits (0 is considered even)! For example, printEvens(433, 452) would create and return a new list with the following values: [440, 442, 444, 446, 448] NOTE: EACH and EVERY digit MUST be an EVEN number, NOT simply that the entire number itself be EVEN!

Using the main below:

import math import random import string import collections import datetime import re import time import copy # YOUR CODE BELOW... def checkRegex(str2) : your code here... # end def def fancyList( ) : your code here... # end def def natureSequence(fn, sn, n) : your code here... # end def def printEvens(a, b) : your code here... # end def def generatePokerHand(deck, coords) : your code here... # end def def main( ) : rv = checkRegex("abcdefghijklmnopqrstuvwxyz") print(rv) rv = checkRegex("Mariner!") print(rv) rv = checkRegex("acdefGhij*012345") print(rv) fancyList( ) rv = natureSequence(0, 1, 10) rv = natureSequence(1, 3, 15) printEvens(433, 452) printEvens(2048, 2188) deck = [["2C", "3C", "4C", "5C", "6C", "7C", "8C", "9C", "XC", "JC", "QC", "KC","AC"], ["2D", "3D", "4D", "5D", "6D", "7D", "8D", "9D", "XD", "JD", "QD", "KD", "AD"], ["2H", "3H", "4H", "5H", "6H", "7H", "8H", "9H", "XH", "JH", "QH", "KH", "AH"], ["2S", "3S", "4S", "5S", "6S", "7S", "8S", "9S", "XS", "JS", "QS", "KS", "AS"] ] coords=["22", "0A", "38", "1B", "25"] rv = generatePokerHand(deck, coords) coords=["23", "24", "25", "26", "27"] rv = generatePokerHand(deck, coords) # end main( ) if __name__ == "__main__" : main( )

Only code for printEvens.