Question: Q7(10 points)Here we want to consider int xe^(x)dx using integration by parts in two different ways.(a) Try u=e^(x) and dv=xdx. What does integration by parts

Q7(10 points)Here we want to consider \int xe^(x)dx using integration by parts in two different ways.(a) Try u=e^(x) and dv=xdx. What does integration by parts give? (it doesn't really help... makes an integralthat might be harder).(b) Now try u=x and dv=e^(x)dx and write out integration by parts and hence get the answer.The idea in both Q6 and Q7 is to show that if you have x^(n) to some integer n>=1 you probably want to takeu=x^(n) and when you write out du you will lose a power and hopefully this makes it easier.Comment on integration by parts. It generally takes longer to use integration by parts than uu substitution first

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