Question $1$

$\frac{0}{1}pt100$

$29$

De

Find $y^{\text{'}}$ by $($a$)$ applying the Product Rule and $($b$)$ multiplying the factors to produce a sum of simpler term. to differentiate.

$y=(9-x^2)(x^{3}x2)$

a$.$ Apply the Product Rule. Let $u=9-x^2$ and $v=z^{3}z2.$

$($:$\frac{d}{dx}(uv)-(9-x^2)\}$

b$.$ Multiply the factors of the original expressign, wand $v,$ to produce a sum of simpler terms.

$y=$

Find $y\text{'}$

$y^{\text{'}}=$