Question: Question (1): [7 points] (a) Shetch Delta H versus Q curve for a three-pump system where the pumps operate (i) in serious, and (ii) in
Question (1): [7 points]\ (a) Shetch
\\\\Delta Hversus
Qcurve for a three-pump system where the pumps operate (i) in serious, and (ii) in parallel. The pumps are all identical.\ (b) A PVC pipeline conveys heptane at a rate of
0.1(m^(3))/(s). Determine the optimum economic pipe size for the installation and the percentage change in volumetric flow rate corresponding to the economic relocity; given that:\
{(:[C_(2)]
=$(0.05)/(k)wh,n=[
1.2]),(C_(1)=$(1300)/(m^(n+1)),a=(1)/(10)=0.10),(t=4000h(r)/(y)r,b=0.01),(F=6.75,\\\\eta =0.75):},D_(op)=[(4(0)m^()^(3)C_(2)l)/(n(a+b)(1+F)C_(1)\\\\eta \\\\pi ^(2)\\\ ho ^(2))]^((1)/(n+3)),\ (Note that the cost of
$0.05must be divided by 1000 )\
D_(opx)=[(4(0)m^(3)C_(2)t)/(n(a+b)(l+F)C_(1)\\\\eta \\\\pi ^(2)-\\\ ho ^(2))]^((1)/(\\\\pi ^(3))) ![Question (1): [7 points]\ (a) Shetch \\\\Delta H versus Q curve](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66efcfc433e13_32366efcfc3b336e.jpg)
(a) Shetch H versus Q curve for a three-pump system where the pumps operate (i) in serious, and (ii) in parallel. The pumps are all identical. (b) A PVC pipeline conveys heptane at a rate of 0.1m3/s. Determine the optimum economic pipe size for the installation and the percentage change in volumetric flow rate corresponding to the economic relocity; given that: C2=$0.05/kwhC1=$1300/mn+1t=4000hr/yrF=6.75costof$0.05mustbedividedby1000)n=1.2a=1/10=0.10b=0.01=0.75Dopx=[n(a+b)(1+F)C1224()m3C2t]n+31, ( Fote that the cost of $0.05 must be divided by 1000 ) (a) Shetch H versus Q curve for a three-pump system where the pumps operate (i) in serious, and (ii) in parallel. The pumps are all identical. (b) A PVC pipeline conveys heptane at a rate of 0.1m3/s. Determine the optimum economic pipe size for the installation and the percentage change in volumetric flow rate corresponding to the economic relocity; given that: C2=$0.05/kwhC1=$1300/mn+1t=4000hr/yrF=6.75costof$0.05mustbedividedby1000)n=1.2a=1/10=0.10b=0.01=0.75Dopx=[n(a+b)(1+F)C1224()m3C2t]n+31, ( Fote that the cost of $0.05 must be divided by 1000 )
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