Question $18$ of $25$

Evaluate the integral using the Fundamental Theorem of Calculus, Part I.

${\displaystyle \underset{\frac{8}{27}}{\overset{1}{}}}\frac{24t^{\frac{4}{3}}-22t^{\frac{1}{3}}}{t^2}dt$

$($Express numbers in exact form. Use symbolic notation and fractions where needed.$)$

${\displaystyle \underset{\frac{8}{27}}{\overset{1}{}}}\frac{24t^{\frac{4}{3}}-22t^{\frac{1}{3}}}{t^2}dt=$

$$