Question: Consider the function fx)=sin 2m We want to approximate the value of | fx)dx in three ways. Copy and paste the numerical answers you

Consider the function fx)=sin 2m We want to approximate the value of

Consider the function fx)=sin 2m We want to approximate the value of | fx)dx in three ways. Copy and paste the numerical answers you get from Julia (if any). Don't round. Using the right Riemann sum with n=1000, the result is: Using the left Riemann sum with n=1000, the result is: Using the Gau-Kronrod quadrature method, the result is: One of the results is very different from the others. Which one is it, and why did it come out so differently?

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