Question $1$

In the structure shown P$1=28kN,P2=42kN,$ and $W=6k\frac{N}{m}.$ The pins at $A,B,$ and $D$ are to be made of steel having ultimate shearing stress equal to $320$Mpa, and Link $AB($link thickness $=10mm)$ is to be made of steel having ultimate normal stress equal to $570$MPa. And given that factor of safety for shear stress will be $4\mathrm{.}5$ and for normal stress will be $4\mathrm{.}8.$ Given also that the allowable bearing stress is equal to $340$Mpa,$L1=0\mathrm{.}4m.$ Answer the questions in the table below: $($ALL PINS ARE IN DOUBLE SHEAR$)$

Select the closest choice to your solution and ONLY TYPE THE LETTER IN THE BLANK $($A$,$ B$,$ C$,$ D$).$

$($Q$1)$ Determine the force in member $AB$ is:

A$.-9\mathrm{.}1KN.$

B$.-4\mathrm{.}79KN.$

C$.-12\mathrm{.}1KN.$

D$.-7\mathrm{.}58KN.$

Answer for $($Q$1)$: Blank $1$

$($Q$2)$ Determine the support Reaction at $D$ is:

A$.110\mathrm{.}03KN.$

B$.82\mathrm{.}73KN.$

C$.43\mathrm{.}54KN.$

D$.68\mathrm{.}94KN.$

Answer for $($Q$3)$: Blank $2$

$($Q$3)$ Determine the diameter of the pin at D with respect to shearing strength :

A$.36\mathrm{.}18mm.$

B$.27\mathrm{.}2mm.$

C$.14\mathrm{.}32mm.$

D$.22\mathrm{.}67mm.$

Answer for $($Q$4)$: Blank $3$

$($Q$4)$ Determine the width of the Link AB :

A$.4\mathrm{.}02mm.$

B$.7\mathrm{.}63mm.$

C$.10\mathrm{.}15mm.$

D$.6\mathrm{.}36mm.$

Answer for $($Q$5)$: Blank $4$

$($Q$5)$ Determine the required thickness of the bracket supports at D with respect to the given bearing strength :

A$.11\mathrm{.}89mm.$

B$.8\mathrm{.}94mm.$

C$.4\mathrm{.}71mm.$

D$.7\mathrm{.}45mm.$

Answer for Type: FMB: Blank $5$