Question: Question 1 R R: 0000-W A current is being supplied from a source with a peak voltage of 18.0 V. What is the current that

 Question 1 R R: 0000-W A current is being supplied from

a source with a peak voltage of 18.0 V. What is the

Question 1 R R: 0000-W A current is being supplied from a source with a peak voltage of 18.0 V. What is the current that is being supplied when the frequency is very small? R1 = 66.0 0, Ry = 17.0 0, Z = 72.0 mH and C = 25.0 PF. Current due to very small frequency: Question 2 The "over-the-air" television channel 5 operates between frequencies 76 MHz and 82 MHz, with the video and audio using different parts of this frequency range. To watch (and listen) to the channel properly, the tuner circuit in a television must resonate in the middle of this range (79 MHz) and produce a current over the whole range of at least 50% of the peak current at resonant frequency. A particular television tuning circuit is built with a 12.7 pF capacitor, a variable inductor, and a variable resistor. What value should the resistor be in order for the current at both 76 MHz and 82 MHz to be at least 50% of the current at the resonant frequency? Hint: You'll have to first calculate the value of the inductor so that the television tunes to channel 5

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