QUESTION 19 In the code below, 2 threads are created and ran with two objects (that would be actual data in a more complete program.) The output from this program is: Thread 1: Holding lock 1. Thread 2: Holding lock 2... Thread 1: Waiting for lock 2... Thread 2: Waiting for lock 1.. What is this situation called? public class TestThread ( public static Object Lock1 public static Object Lock2 new Object); new Object): public static void main(String args0) Thread1 T1 new Thread10: Thread2 T2 new Thread20: T1.start0: T2.start): private static class Thread1 extends Thread ( public void runo ( synchronized (Lock1) ( System.out.printin( Thread 1: Holding lock 1...": try (Thread.sleep(10);) catch (InterruptedException e) 0 System.out.printin("Thread 1: Waiting for lock 2.." synchronized (Lock2)( System.out.printin("Thread 1: Holding lock 1 &2.." private static class Thread1 extends Thread ( public void runo ( synchronized (Lock1)f System.out.println("Thread 1: Holding lock 1..."); try ( Thread.sleep(10): ) catch (InterruptedException e) 0 System.out.println("Thread 1: Waiting for lock 2.."; synchronized (Lock2) ( System.out.println("Thread 1: Holding lock 1 &2...") private static class Thread2 extends Thread f public void runo ( synchronized (Lock2) ( System.out.println("Thread 2: Holding lock 2..."); try (Thread.sleep(10):) catch (InterruptedException e)0 System.out.println("Thread 2: Waiting for lock 1..."): synchronized (Lock1) ( System.out.println("Thread 2: Holding lock 1 &2.." Asynchronous threading Race Condition D www.science-intera... Exploring Science www.science-intera...G y Question Completion Status: private static class Thread2 extends Thread ( public void runo ( synchronized (Lock2) ( System.out.println"Thread 2: Holding lock 2..": try ( Thread.sleep(10); ) catch (InterruptedException e) 0 System.out.println("Thread 2: Waiting for lock 1..."); synchronized (Lock1) t System.out.println("Thread 2: Holding lock 1 &2.") Asynchronous threading Race Condition Deadlock condition Synchronisation collapse QUESTION 20 When your app starts up on Android it is assigned to a Main thread, ensure that work is spread out (and take advantage of multiple cores But what can you not access directly from threads you create