Question: Question 2 [ 1 6 points ] A person drives a large diesel - fueled truck from Riyadh to Jeddah at an average speed of

Question 2[16 points]
A person drives a large diesel-fueled truck from Riyadh to Jeddah at an average speed of 110kmh. The distance he traveled is 990km. During this trip, the power consumption is given by the following equation:
P=Pacc+Ptire+Paero
Where, Pacc=20(kW)
Ptire=ctireV, where is in kmh, and the result is in kW
Paero=cacroV3, where is in kmh, and the result is in kW
To reduce diesel consumption on his way back from Jeddah to Riyadh, the driver decides to do the following:
Properly inflate the tires to reduce ctire by 20%
Install aerodynamic additives to reduce caero by 15%
Drive at 90kmh
The power consumed by the accessories (Pacc) remains the same during the return trip.
The efficiency of the diesel engine is 30%(defined as: power output / rate of heat input from diesel), and the price of diesel is SR 0.75/liter. The heating value of a liter of diesel is 36MJ.
a. How many liters of diesel does the driver consume on the first trip (from Riyadh to Jeddah)?[5 points]
b. How many liters of diesel does the driver consume on the second trip (from Jeddah to Riyadh)?[6 points]
c. Calculate the savings (in Saudi Riyals) the driver made in fuel cost in the second trip. [5 points]
 Question 2[16 points] A person drives a large diesel-fueled truck from

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