Question $2$

A statically indeterminate frame is shown. The following distribution factors can be calculated : DF$\_($BA$)$

$=0\mathrm{.}384,$DF$\_($BC$)=0\mathrm{.}616$;DF$\_($CB$)=0\mathrm{.}586,$DF$\_($CD$)=0\mathrm{.}414.$ Use P$=55$kN$.($E$)/()$ is constant for the frame.

Use E$=200$GPa,I$=100\backslash$times $10^(-6)$m$^(4).$

aB$.$ What is the

value of R$\_(1),$ the force preventing sway?

b$\backslash$psi $\_($AB$)=\backslash$psi are $\backslash$psi $\_($BC$)=-1\mathrm{.}667\backslash$psi and $\backslash$psi $\_($CD$)=\backslash$psi $.$ Fixed end moments in AB are assumed

as follows: FEM$\_($AB$)=$FEM$\_($BA$)=-50$kNm$.$ What are the corresponding fixed end moments due to sway

in elements BC and CD $?$

FEM$\_($BC$)$:$,$ kNm

FEM$\_($CB$)$:$,$kNm

FEM$\_($CD$)$:$,$ kNm

FEM$\_($DC$)$:$,$ kNm