Question 2 Maximum Word Count 1000 words Refer to Table 1. This table shows normal durations and costs, and crash durations and costs for the activities involved in one of the main project packages. Table 1 - Activity normal and crash durations for the package Note: The crash duration represents the minimum duration where an activity is speeded up as much as possible. The crash cost represents the increased cost of the activity after it has been speeded up as much as possible. Note: Where the normal duration and crash duration are the same this activity cannot be crashed Activity A-B A-C A-E B-D C-G C-H D-F D-H E-F F-J F-K G- H-1 H- EL J-L K-L Normal duration (months) 8 3 3 5 2 6 6 4 3 9 2 1 3 3 2 11 2 Crash duration (months) 6 1 1 4 2 2 2 3 3 7 1 1 2 1 1 8 2 Normal cost (6) 100,000 100.000 500,000 150.000 30,000 5,000 100,000 80,000 30,000 150,000 30.000 300,000 80,000 160.000 30,000 100,000 600.000 Crash cost (9) 200.000 120,000 700.000 230,000 30.000 5,000 160,000 130,000 30.000 190,000 40.000 350,000 160,000 210,000 35,000 139,000 700.000 (a) (b) Draw a network for the work package showing the activities, critical path and package duration (5 marks) Assume TVO wishes the package to be completed within 28 months. Calculate the most cost-effective way of completing the package within this time, giving the final work package cost associated with this crash sequence. (10 marks) Assume liquidated and ascertained damages apply at a rate of 5,000 per week for completion later than the end of month 27. Calculate the actual costs of crash and present it in a graphical report'. Explain what the duration is that gives the lowest total project cost (10 marks) (Total 25 marks) (c) Question 2 Maximum Word Count 1000 words Refer to Table 1. This table shows normal durations and costs, and crash durations and costs for the activities involved in one of the main project packages. Table 1 - Activity normal and crash durations for the package Note: The crash duration represents the minimum duration where an activity is speeded up as much as possible. The crash cost represents the increased cost of the activity after it has been speeded up as much as possible. Note: Where the normal duration and crash duration are the same this activity cannot be crashed Activity A-B A-C A-E B-D C-G C-H D-F D-H E-F F-J F-K G- H-1 H- EL J-L K-L Normal duration (months) 8 3 3 5 2 6 6 4 3 9 2 1 3 3 2 11 2 Crash duration (months) 6 1 1 4 2 2 2 3 3 7 1 1 2 1 1 8 2 Normal cost (6) 100,000 100.000 500,000 150.000 30,000 5,000 100,000 80,000 30,000 150,000 30.000 300,000 80,000 160.000 30,000 100,000 600.000 Crash cost (9) 200.000 120,000 700.000 230,000 30.000 5,000 160,000 130,000 30.000 190,000 40.000 350,000 160,000 210,000 35,000 139,000 700.000 (a) (b) Draw a network for the work package showing the activities, critical path and package duration (5 marks) Assume TVO wishes the package to be completed within 28 months. Calculate the most cost-effective way of completing the package within this time, giving the final work package cost associated with this crash sequence. (10 marks) Assume liquidated and ascertained damages apply at a rate of 5,000 per week for completion later than the end of month 27. Calculate the actual costs of crash and present it in a graphical report'. Explain what the duration is that gives the lowest total project cost (10 marks) (Total 25 marks) (c)