Question 2

using python jupyter

The days of the year are often numbered from 1 through 365 (or 366). This number can be computed in three steps using int arithmetic: (a) dayNumber = 31(month - 1) +day (b) if the month is after February subtract (4(month) + 23)//10 (c) if it's a leap year and month after February, add 1 Write a program that reads the day, month, and the year. Then, it calculates the corresponding day number. A leap year is a year with 29 days. A leap year is a year (divisible by 4 but not by 100) or divisible by 400. The number of days in each month are as follows: months 1,3,5,7,8,10,12 have 31 days months 4,6,9,11 have 30 days month 2 has 28 days for non leap year and 29 for leap year. Assume that the user will enter integer values as input. A valid year is any year >= 1. A valid month is between 1 and 12 For days, valid input is according to the month number as defined above.

Sample run 1 Enter year number: -2 Wrong input: year must be >= 1

Sample run 2 Enter year number: 1950 Enter month number: 13 Wrong input: month must be from 1 to 12

Sample run 3 Enter year number: 1990 Enter month number: 11 Enter day number: 31 Wrong input: your day must be in [1,30] range

Sample run 4 Enter year number: 1990 Enter month number: 12 Enter day number: 32 Wrong input: your day must be in [1,31] range

Sample run 5 This case for leap year Enter year number: 2000 Enter month number: 3 Enter day number: 1 The day number is: 61

Sample run 5 This case for non leap year Enter year number: 1999 Enter month number: 11 Enter day number: 25 The day number is: 329

In [ ]:

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