Question: Use python to solve (use if else elif or and only): The days of the year are often numbered from 1 through 365 (or 366).

 Use python to solve (use if else elif or and only):

Use python to solve (use if else elif or and only): The days of the year are often numbered from 1 through 365 (or 366). This number can be computed in three steps using int arithmetic: (a) davNumber =31( month 1) +day (b) if the month is after February subtract (4( month )+23)//10 (c) if it's a leap year and month after February, add 1 Write a program that reads the day, month, and the year. Then, it calculates the corresponding day number. A leap year is a year with 29 days. A leap year is a year (divisible by 4 but not by 100 ) or divisible by 400 . The number of days in each month are as follows: months 1,3,5,7,8,10,12 have 31 days months 4,6,9,11 have 30 days month 2 has 28 days for non leap year and 29 for leap year. Assume that the user will enter integer values as input. A valid year is any year >=1. A valid month is between 1 and 12 For days, valid input is according to the month number as defined above

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