. Question 2 v V Part1of4 22 24 27 27 27 29 Consider the population data shown in the table above. We will build a table to find the population standard deviation, 0'. a. First, we need to find the population mean (round to one decimal): ,u = 26 s/ 0' Y Part20f4 Next, we fill in the deviations column. a: a: ,u 22 24 27 27 27 29 Do this on a separate sheet of paper. Then enter the deviation of the value a: = 22. Keep the sign if it's negative. b.Whenx=22,m,u= 0\" c. Based on your table, what is Z (a: ,u)- 0'9 d. Without any rounding, what value would you expect for Z (a: p)? 0'9 Y Part30f4 Your table should match the table shown below. Since 2: (a: u) = 0 we square the deviations so that positive and negative deviations don't cancel each other out. Add the squares of your deviations to your table. Then enter the value you got that corresponds to a: = 22 e.Whena:=22,[a:p)2= 16 \\/ o" f. Based on your table, what is Z (:1: pf? cl\" Part 4 of 4 IouL-rul -1 Your table should match the table below. The last entry of the third column is the sum. 3 I .u (=13 #32 22 -4 1e 24 -2 4 27 1 1 27 1 1 27 1 1 29 3 9 32 Now we just divide the sum of the last column by N to get the variance. Round to four decimals. 2 2(3_ )2 Finally, take the square root of the variance to get the standard deviation. Round to two decimals