Question $3(1$ point$)$

Suppose a function is defined by $h(x)=\frac{1}{(x1{)}^2}$

Consider the improper integral ${\displaystyle \underset{2}{\overset{}{}}}h(x)dx$

The integral converges to a value between $0$ and $0\mathrm{.}1.$

The integral diverges.

The integral converges to a value between $0\mathrm{.}3$ and $0\mathrm{.}5.$

The integral converges to a value between $0\mathrm{.}1$ and $0\mathrm{.}3.$