Question: Question 3 1 pts Consider the following stem and leaf plot that shows the LDL cholesterol levels (in milligram per deciliter [mgfd L]) for nonsmokers.

 Question 3 1 pts Consider the following stem and leaf plotthat shows the LDL cholesterol levels (in milligram per deciliter [mgfd L])for nonsmokers. The digits in the stem represents the hundreds and tens,and the digit in the leaf represents the ones. So for example11 | 8 = 118. non smokers 11103 111539 12 3668899 13017\"339 1-4 015691 15 24.1 15 013 17 46 1 18 1920 From wwwanalyzemathcom Which of the following LDL values is not representedin the stem plot? O 160 O 151 O 119 O 176Question 4 1 pts If the power of a statistical test wasfound to be 0.73, how would you calculate the probability of atype ll error? O P(z0.73) O 2*P(Z=3 servings of alcohol on most

days; we will refer these men as "heavy drinkers," or "hd." Theirsample average serum cholesterol was (xbar=) 210 mg/dL. The 95% CI forthe true average population serum cholesterol in this population of heavy drinkerswas {187 mgde, 233 mgde}. Assume that investigators wish to test H0:u {for heavy drinkers)=240 mngL vs. Ha: u {for heavy drinkers) ==240 md/dL. Select the best response. 0 Because 240 mngL is notin the 95% condence interval. we expect the p value for thistest would be less than or equal to 0.05. 0 Because 240mngL is not in the 95% condence interval, we expect the pvalue for this test would be greater than or equal to 0.05.(3) There is no relationship between the 95% Cl and the p

Question 3 1 pts Consider the following stem and leaf plot that shows the LDL cholesterol levels (in milligram per deciliter [mgfd L]) for nonsmokers. The digits in the stem represents the hundreds and tens, and the digit in the leaf represents the ones. So for example 11 | 8 = 118. non smokers 11103 111539 12 3668899 13 017\"339 1-4 015691 15 24.1 15 013 17 46 1 18 19 20 From wwwanalyzemathcom Which of the following LDL values is not represented in the stem plot? O 160 O 151 O 119 O 176 Question 4 1 pts If the power of a statistical test was found to be 0.73, how would you calculate the probability of a type ll error? O P(z0.73) O 2*P(Z=3 servings of alcohol on most days; we will refer these men as "heavy drinkers," or "hd." Their sample average serum cholesterol was (xbar=) 210 mg/dL. The 95% CI for the true average population serum cholesterol in this population of heavy drinkers was {187 mgde, 233 mgde}. Assume that investigators wish to test H0: u {for heavy drinkers)=240 mngL vs. Ha: u {for heavy drinkers) == 240 md/dL. Select the best response. 0 Because 240 mngL is not in the 95% condence interval. we expect the p value for this test would be less than or equal to 0.05. 0 Because 240 mngL is not in the 95% condence interval, we expect the p value for this test would be greater than or equal to 0.05. (3) There is no relationship between the 95% Cl and the p value the stated hypothesis test

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