Question 3 (10 pts): Memory Map Practice

a) In order to debug an embedded application or to understand an embedded application developed by someone else, it is often necessary to understand how data memory is modified by C code statements. Fill in the given memory map after the C fragment below has been executed. Note: The TM4C123 uses Little Endian ordering for memory (i.e. lower significant bytes of an element are stored at lower addresses). (7 pts)

char msg[4] = Sal;

short age[1] = {0x2070};

int speed[2];

msg[3] = 0x61;

msg[1] = 0x6F;

age[0] = age[0] + 2;

speed[0] = 0x696C6345;

age[3] = 0x7370;

age[4] = 0x65;

printf(%s, msg);

Memory Location

0xFF00

0xFF01

0xFF02

0xFF03

0xFF04

0xFF05

0xFF06

0xFF07

0xFF08

0xFF09

0xFF0A

0xFF0B

0xFF0C

0xFF0D

Value

Array

msg

age

speed

Index

0

1

2

3

0

0

1

b) What message will printf print for part a) (3 pts)

Question 3 (10 pts): Memory Map Practice a) In order to debug an embedded application or to understand an embedded application developed by someone else, it is often necessary to understand how data memory is modified by C code statements Fill in the given memory map after the C fragment below has been executed. Note: The TM4C123 uses Little Endian ordering for memory (i.e. lower significant bytes of an element are stored at lower addresses).(7 pts) char msq[4] "Sal"; short age [1] {0x2070}; int, speed [2]: msg [3] msg [1] 0x61; 0x6F; age [0] = age [0] + 2; speed [0] 0x696C6345; age [3] age [4] = 0x7370; = 0x65; printf("%s", msg); Mem Location 0xFF00lOxFF01 0xFF02 0xFF03 0xFF04 0xFF05 0xFF06 0xFF07 0xFF08 0xFF09 0xFFOAlOxFFOB 0xFFOCIOxFFOD Value ms age speed Index0 0 0 1 b) What message will printf print for part a)(3 pts)