Question 3 (30 points) A solute A is being absorbed from a gas mixture of A and B to a liquid in an absorption tower as shown in the figure below. The solute A diffuses through non- diffusing B in the gas phase and then through the non-diffusing liquid. The mole fractions of Ain the gas phase and in the liquid phase are shown with y and x, respectively. V2= 60.71 kmol/h Ya= 0.0075 L3=71.00 kmol/h X = 0.0000 Absorption Column V = 63.09 kmol/h YI= 0.0450 L = ? kmol/h Xi=? After some preliminary calculations, the following data are obtained. At the bottom of the tower At the top of the tower (location 1) (location 2) y = 0.0250 y = 0.0000 Further data: Tower's cross-sectional area, S, is 0.400 m. Kya = 5,500x102 kmol/(m's mol frac.). Show your calculations explicitly. (a) Calculate the flow rate of the liquid at the bottom of the tower (L) and the mole fraction of A in the liquid at the bottom of the tower (x1) using material balances. (b) Calculate the tower height z in meters