Question: Question 3 (9 points) Consider the following problem faced by a Dietician: A diet needs to be created that contains not less than 1777 calories,
Question 3 (9 points)
Consider the following problem faced by a Dietician:
A diet needs to be created that contains not less than 1777 calories, not more than 79 grams of protein, not less than 17 grams of carbohydrates and not less than 13 grams of fat. Also, the diet should have minimal cost. In addition the diet should include at least 1.3 Units of fish and at least 0.8 cup of milk.
The diet will consist of the six different foods: Bread, Milk, Cheese, Fish, Potato and Yogurt. The following table lists the cost per unit of each item and the number of grams of protein, fat, and carbohydrates per unit as well as the calories that will be supplied by each food unit.
|
| Bread | Milk | Cheese | Potato | Fish | Yogurt |
| Cost, (cents) | 13 | 27 | 33 | 14 | 101 | 23 |
| Protein, g | 4 | 10 | 13 | 2.3 | 14 | 15.2 |
| Fat, g | 2 | 8 | 13 | 0.1 | 7 | 3 |
| Carbohydrates, g | 23 | 22.7 | 0.4 | 31.6 | 0 | 32 |
| Calories, Cal | 178 | 184 | 180 | 137 | 207 | 344 |
Find a diet that meets the requirements above while keeping the cost at an absolute minimum. Make sure that your Food Units are all Integers. Minimum Cost =
(Cents) Hint: Min Cost value is between 306 and 327 Number of Units of Each Item Make sure your answers are INTEGERS Bread = Milk= Cheese= Potato= Fish= Yogurt=
Question 4 (9 points)
The Rapid City Chamber of Commerce periodically sponsors public service seminars and programs which are open to the public. Currently, promotional plans are under way for this years program. Advertising alternatives include television, radio, and newspaper. Audience estimates, costs, and maximum media usage limitations are shown below:
|
| Television | Radio | Newspaper |
| Audience per advertisement | 80,000 | 10,000 | 50,000 |
| Cost per advertisement | $1,500 | $290 | $540 |
| Maximum media usage limitation | 15 | 25 | 10 |
Suppose that the production budget is limited to $35,000. We are limited to run at most 43 Ads in all three mediums combined. We need to determine how many commercial messages should be run on each medium so as to reach as many people in Rapid City as possible. Optimal Solution: Number of TV Ads = Number of Radio Ads = Number of Newspaper Ads = Total Audience Reached =
Hint: Value should be between 1879300 and 1881700 The Total Cost to buy all of these Ads will be $ DO Not Format your answers . Leave off Dollar Signs and Commas
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