Question 4 [4 marks) Consider the following Bayesian game. Player1 can be of type r E [4, 6} where Pr(t = 4) = 0.6. Player 1 knows his type, but Player 2 only knows the prior distribution of 1's type. Call 64 Player 1's probability of playing A if he is type 4, 56 Player 1's probability of playing A if he is of type 6, and a, Player 2's probability of playing C. There is a BNE in which all player types play mixed strategies. and 0'4 = 0'6. In it, 64 = 66 = 0}: Make sure you round your answers to 3 decimal places if necessary