Question. 4: Activity In the given table and network diagram below, a small engineering project activities durations and direct costs under both normal and crash conditions are provided. Normal Crash Cost Preceded Duration Cost Duration by Cost Slope (day) (SR) (day) (SR) (SR day) A 7 3600 6 3900 300 B A 5 5500 3 6500 500 C B 9 6350 7 7200 ? D B 19 4700 18 4900 200 E B 10 2050 9 2200 150 F C 8 1200 7 1450 250 G F 5 7200 5 7200 H E 11 9450 10 10000 550 D, G, H 4500 5 4600 50 I 7 It is required to crash the project duration from its original duration to a final duration of 38days. Assume an indirect cost of SR 200/day. Use Project information to perform all needed cycles and use them to answer the following questions: What is the cost slope for activity C? What is the cost slope for activity G? In order to reduce the project duration which activity/activities would be crashed in cycle#1? In order to reduce the project duration which activity/activities would be crashed in cycle#2? In order to reduce the project duration further (1.e. less than 38 days) which activity/activities would be crashed next? by how many days the project can be shortened in cycel # 1 ? by how many days the project can be shortened in cycel # 2 ? by how many days the project can be shortened in cycel # 3 ? At what duration the total cost direct cost +indirect cost) is the smallest optimal duration)