Question 4. {Series solutions - 'lst order equation] Question 4. {Series solutions 1st order equation} This question relates to the differential equation y'(225)y=0. You should be familiar with the material from Chapter 4, sec. 4.1 -4.3 when you attempt this question. Question 4.1 Find the recurrence relation for the coefficients of the power series solution in y = Earns" n= of (3}. Rearrange the relation to the form Gn+1 = . . . In the eld below, enter the right hand side of this equation. Use a[n]r a[n-1] to enter expressions with subscripts. For example, if your solution is _ (n+1]a.n GnuT then your answer must be entered as [n+1 ]*a[n].."(2*n}. Enter your answer here Question 4.2 Use the recurrence relation that you obtained in Question 4.1 to calculate coefficients of the series solution that satises the initial condition 3(0) = -3 up to the quadratic tern-I, i.e. you need to caclulate coefficients in the polynomial y = \"D + a1: + 112:2. Enter the expression for an + a1: + cm:2 in the field that follows. For example, if your answer is y=1+2:.-+3:r2 then it should be entered as 'l+2*x+3*x"'2 Enter your answer here (3)