Question: Question 5 a . A CD test conducted on a normally consolidated clay gave the following results: Confining stress = 1 0 0 kPa. Deviator

Question 5
a. A CD test conducted on a normally consolidated clay gave the following results: Confining stress =100kPa.
Deviator stress at failure =80kPa
i. Calculate the effective friction angle '(in degrees) at failure.
ii. Calculate the shear and normal effective stress on the failure plane
b. In a UU test, the required for failure is 70kPa. Estimate the undrained shear strength.
Question 5 a . A CD test conducted on a normally

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!

Q:

A consolidated undrained ( CU ) triaxial test was conducted on a normally consolidated clay. The cell pressure used was 1 4 0 kPa , The measured deviator stress at failure was 1 2 5 kPa and the...

Q:

1 3 . 1 1 A consolidated - drained triaxial test was conducted on a normally consolidated clay with a chamber pressure, 3 = 2 5 l b i n 2 . The deviator stress at failure is ( u d ) f = 3 3 l b i n 2...

Q:

2 . 1 9 A consolidated - drained triaxial test on a normally consolidated clay yielded the following results: All - around confining pressure = 3 = 1 1 5 k N m 2 Added axial stress a t failure = = 2...

Q:

A consolidated drained tr axial test was conducted on a normally consolidated clay. The results were as follows: Chamber confining pressure = 2 1 5 . 5 KPa Deviator Stress = 3 8 4 Kpa a . Compute the...

Q:

Q - 7 : A consolidated - drained tri - axial test was conducted on a normally consolidated clay. The results are as follows: confining stress 3 = 2 5 0 k N m 2 and deviator stress ( d ) r = 1 5 0 k N...

Q:

A residential block will be constructed on a clay deposit. The building will rest on a mat foundation at 2 m depth and has 2 0 m 2 0 m dimensions in plan. The clay deposit is 2 6 m deep and overlies...

Q:

( 2 0 points total ) A specimen of saturated, normally consolidated clay prepared from an undisturbed sample recovered from a certain depth in the field ( v o ' = 2 7 0 p s f ) was subjected to a CU...

Q:

1. A triaxialtest is performed on a normally consolidated clay.The sample is further consolidatedby the test of all-around confining pressure prior to the application of the axial load.The axial...

Q:

The shear strength of a normally consolidated clay can be given by the equation _ f = ^ tan 3 1 . A consolidated - undrained triaxial test was conducted on the clay. Following are the results of the...

Q:

Question 3 ( a ) Explain why the effective stress path of a drained triaxial compression test has a slope of 1 on the s ' - t ' plane, and a slope of 3 on the q ' - p ' plane. ( b ) The initial...

Q:

Figure 1 shows the shaded region between the graph of functions y = cos(rx) and y = sin(Tx) over the interval Find the area of the shaded region. y = cos (nx) 0.5 -1/2 -1/4 1/4 1/2 3/4 1 5/4 3/2 -...

Q:

With reference to Exercise 11.4 on page 398, use the value of s2 found in Exercise 11.20(a) to compute (a) A 95% confidence interval for the menu shear resistance when x = 24.5; (b) A 95% prediction...

Q:

Question 7 1 pts The market has an expected rate of return of 6 . 5 percent. The long - term government bond is expected to yeld 4 . 5 percent and the U . S . Treasury bill is expected to yield 1 . 8...

Q:

Book Just One Product (JOP) began operating on June 26 with no inventory on hand. It then made the purchases listed below. JOP sold and delivered 46 units on June 30. Date June 27 June 28 June 29...