Question: Question 5 A vertical spring a force constant of 100 N/m is resting at its equilibrium position. A 2 kg block is attached to

Question 5 A vertical spring a force constant of 100 N/m is resting at its equilibrium position. A 2 kg block is attached to the spring and released from rest from the equilibrium position. When the block reaches a speed of 2 m/s downward, a. How far has the block fallen? b. Is the gravitational potential energy increasing or decreasing? c. Is the spring potential energy increasing or decreasing? d. What is the lowest point that the block will fall? 100 N/m equilibrium position www. IM 2 kg mmo 2 kg 2 m/s
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a the block will fall if gravitational force is more ... View full answer
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