Question #6: [15 points] The data provided below show a frequency distribution of the number of lifetime convictions among 4,615 men from the Netherlands who all were convicted in 197T. Fiist, compute all three measures of central tendency for these data (mode, median, and mean) To compute the mean, you should treat the midpoint of each interval (i.e., the average of the lower and upper interval limits} as your value for a.' Because the last interval is not hounded, use 53 as the midpoint to maintain consistency. Second, compute all three measures of dispersion for these data (variation ratio, interquarte range, and standard deviation]. Use both the denitional and computational formulas for standard deviation. Number of Convictions p 0 0.1138 1 - 5 0.464 6 - 1|] 0.166 11 - 15 0.161 16 - 21] 0.661 21 - 25 0.641 26 - 31] 0.632 31 35 0.018 36 - 41] 0.61? 41 - 45 0.611] 46 - 51] 0.11118 51+ 0.1144 1.000