Question #6: [I 5 points] The data provided below show a frequency distribution of the number of lifetime convictions among 4,615 men from the Netherlands who all were convicted in 197?. First, compute all three measures of central tendency for these data (mode, median, and mean) 'Ib compute the mean, you should treat the midpoint of each interval (i.e., the average of the loser and upper interval limits} as your value for 3 Because the last interval is not bounded, use 53 as the midpoint to maintain consistency. Second, compute all three measures of dispersion for these data (variation ratio, interquartile range, and standard deviation]. Use both the denitional and computational formulas for standard deviation. Number of Convictions p 0 0.638 1 - 5 0.464 6 - 16 0.166 11 - 15 0.101 16 - 26 0.661 21 - 25 0.641 26 - 36 0.632 31 - 35 0.618 36 - 46 0.617 =11 - 45 0.616 :16 - 56 0.668 51+ 0.644 1.666