Question: Question 6 (Mandatory) (1 point) A line has parametric equations x=2+3t y=1+2t z = -6 - t, for t that belongsto the family of real





![normal vector #? = [0, -1, 0] and having a y-intercept 3.](https://s3.amazonaws.com/si.experts.images/answers/2024/07/66879e6c69194_94866879e6c4c030.jpg)
Question 6 (Mandatory) (1 point) A line has parametric equations x=2+3t y=1+2t z = -6 - t, for t that belongsto the family of real values R. A vector parallel to the line is: Q a) not listed 0 b>(2,1,-6) Q 6) (6,4,2) Q d) (3,2,1) Question 3 (Mandatory) (1 point) Write the scalar equation of the plane with normal vector #? = [0, -1, 0] and having a y-intercept 3. (a) x + z + 3 = 0 (by- 3=0 Ocl y + 3 =0 O d) 3 y- 3 =0Question 7 (Mandatory) (1 point) Given the parametric equations of a line, x = 3 + 5t,y = 2 - t,z = 3 + 2t, for tis real value Find the equation of the same line in vector form. Exactly one option must be correct) a) ( x,y, z) = (3, 2, 3) + t (5, - 1, 2 ) ( b) ( x, y, z) = (5, - 1, 2) +t(- 3, -2, -3) ( c) ( x,y,z)= (8, 1, 5) +t (5, 1, 2) O d) ( x, y,z) = (5, - 1, 2) + t (3, 2, 3)Question 5 (Mandatory) (1 point) Find the equation of the line joining points P(2,1,-1) and Q(O,3,1), in vector form. (Exactly one option must be correct) Q a) (x,y,z)=(2,4,0)+t(2,1,-1) O b) (x,y,z)=(2,2,2) +t(2,1,-1) O c) (x,y,z)= (2,1,-1)+ t(0,3,1) Q d) (x,y,z) =(2,1,-1) +t(-2,2,2) Question 8 (Mandatory) (1 point) Find the equation of the line I through (1,2,1) parallel to the line given by the parametric equations x=2+3t,y= 1+t,z=5+4t,fortany real value. Q a) r = (1, 2, 1) +t( 3, -1, 4) O b) r= (1, 2, 1) +t(6, 2, 8) O c) r =(1, 2, 1) +t(2, 1, 5) Q d) r = (2, 1, 5) +t(3, 1, 4) Question 4 (Mandatory) (1 point) Write the scalar equation of the plane with normal vector '3; [3: 4. 1] and passing through the origin. 0 a) 3x+4y-z- 6 = n
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