Question 7 10 points The project network diagram is listed below and the cost information is provided in the following table Indirect costs associated with normal duration of 25 periods are $350 and for cach period reduction, the savings for indirect costs are $50. Calculate activity crashing slopes and find the optimum cost time B D 6 6 6 4 F 5 3 E 5 - 5 7 Type here to search O i 21 PM Sus 3 23 17 D/ 411 S S A * 7 2 3 a 4 5 6 7 8 o W E R T Y U - o P A S D F G H J J L ? Z C V B N . 1 alt tri Question Completion Status 5 7 The cost information Activity Normal Normal Crash Duration Cost Duration Crash Maximum Crash Cost Crash Cost Times Slope 40 0 4 40 4 B 6 70 2 190 4 6 40 4 90 2 D 6 70 5 90 E 5 80 105 1 F 5 60 1 160 4 G 6 80 2 160 4 H 5 50 4 75 1 - 7 40 6 60 1 3 50 3 SO 0 Question Cat: Calculate crashing slope for each activity and it in the bank with a value without sin corresponding to each activity Type here to search o BE SUS esc 14 16 110 411 95 2 3 4 5 6 7 8 9 ob W 1 E R Y U 1 Sock S D F G H J N C V . N M. Remaining Time 2 hours, 12 minutes, 36 seconds Question Completion Status 1 7 OU 1 3 50 3 50 0 Question C8Q1: Calculate crashings for each activity and fill in the back with a value without responding to achat A. D E F H- 1- J- Type here to search O SUS 2 ES 17 DIS 110 N $ 96 7 2 3 4 5 6 7 8 9 W E R T Y U d S D F G I J K