Question $7$

If $a=(b^2+c^2{)}^{0\mathrm{.}5}$ where $b=c={10}^{-30},$ what is the "infinite precision" solution $($i$.$e$.$ the handsolved solution$)$ when solving for $a?$

a$.0$

b$.{1\mathrm{.}41}^{***}{10}^{-30}$

c$.1$

d$.(1+{10}^{-60}{)}^{0\mathrm{.}5}$