Question $8$

$3$ Points

A parallel plate capacitor of capacitance C $0$ has plates of area A with separation d between them. When it is connected to a battery of voltage V $0,$ it has charge of magnitude Q $0$ on its plates. It is then disconnected from the battery and the plates are pulled apart to a separation $2$d without discharging them. After the plates are $2$d apart, the new capacitance and the potential difference between the plates are

C$0,2$ V$0$

C$0,2$ V$0$

$2$ C$0,2$ V$0$

C$0,$ V$0$

C$0,$ V$0$