Question $8$

$4$ pts

A farsighted person cannot see objects clearly when they are closer than $58\mathrm{.}9$ cm from their eyes. Assuming they wear their glasses $1\mathrm{.}71$ cm in front of their eyes, what is the power of the corrective lens that will let them see an object $23\mathrm{.}2$ cm in front of their eyes clearly?

Enter your answer in units of diopters, or inverse meters. For example, if your calculations result in a value of $1\mathrm{.}23$ D$,$ enter your answer as $1\mathrm{.}23.$