According to the circuit shown, what is the direction of the electric field? C B D...

   

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According to the circuit shown, what is the direction of the electric field? C B D a. From point D to point C O b. From point B to point A From point C to point D Od. From point A to point B -5 For the circuit shown, A calibration curve for the potentiometer wire is obtained. The slope K is equal to: (Note: p is the resistivity of the wire and A is the cross sectional area of the wire) V(volt) slope3K L (cm) a. Ip K = A Ob. Vp K = A Oc. LA K = Od. K=2 LA According to the circuit shown, what is the direction of the electric field? C B D a. From point D to point C O b. From point B to point A From point C to point D Od. From point A to point B -5 For the circuit shown, A calibration curve for the potentiometer wire is obtained. The slope K is equal to: (Note: p is the resistivity of the wire and A is the cross sectional area of the wire) V(volt) slope3K L (cm) a. Ip K = A Ob. Vp K = A Oc. LA K = Od. K=2 LA

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8 The electeic field is always in the direction opposite to that of the flow ... View the full answer