Question: Question 8 The compiler automatically executes two steps behind a for loop: ( 1 ) ECx - ECx - 1 ; ( 2 ) to

Question 8
The compiler automatically executes two steps behind a "for" loop:
(1) ECx-ECx-1; (2) to determine if ECx=0. The following five lines of code are here to implement the two steps above. (Assume there are FIVE iterations)
main PROC
examLoop:
clear ECX with ZERO
MOV ECX, 5 ; initialize ECX with 5
ECX -ECX-1
to determine if ECx=0
q,
if not equal to 0, repeat four steps above
INVOKE ExitProcess, 0
main ENDP
Which line of code should be in the line 8?
ADD ECX, 1
SUB ECX, -1
Both A and C are correct
DEC ECX
MOV -1, ECX
Question 8 The compiler automatically executes

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