The compiler automatically executes two steps behind a "for" loop:

$(1)$ ECxECx$-1$; $(2)$ to determine if ECX $=0.$ The following five lines of code are here to implement the two steps above. $($Assume there are FIVE iterations$)$

main PROC

examLoop:

$$ clear ECX with ZERO

MOV ECX, $5$ ; initialize ECX with $5$

;

; ECX ECX$-1$

$-1$

to determine if ECx$=0$

$\_-11$ if not equal to $0,$ repeat four steps above

INVOKE ExitProcess, $0$

main ENDP

Which line of code should be in the line $9?$

MOV ECX, $0$

Both C and D are correct

CMP ECX, Oh

MOV CX$,$ Oh

TEST ECX, ECX