Question: Question: Can somebody please provide an answer along with excel formulas to this scenario.... 62.5 #N/A A B C D E F G H K

Question: Can somebody please provide an answer along with excel formulas to this scenario....

Question: Can somebody please provide an answer

62.5 #N/A A B C D E F G H K L M N 0 176 SCENARIO A process has a mean of 63.06 and a standard deviation of 0.11 It's lower specification limit is 177 and it's upper specification limit is 63.5 178 15 5 Calculate its Cp. Co- 179 #N/A 180 181 16 2 Explain what this Cp means for the process. 182 183 184 185 17 5 Calculate the Cpk for the above scenario. 186 187 188 18 2 Explain what this Cpk means for the process. 189 190 191 192 19 5 Calculate its S value. S= 193 #N/A 194 195 20 2 Explain what this S value means for the process. 196 197 198 199 21 10 Use the data below to calculate the control limits for an Xbar chart and R chart. (Manager's step in control chart preparation) 200 There are 11 samples with 6 in cach sample. 201 Z= 3 1 2 2 3 4 5 6 7 8 9 10 11 202 XI 9.20 9.18 9.23 9.20 9.20 9.18 9.23 9.20 9.20 9.20 9.20 1203 X2 9.28 9.28 9.24 9.22 9.24 9.28 9.28 9.24 9.28 9.23 9.26 204 X3 9.20 9.19 9.23 1100 9.21 9.20 9.23 9.21 9.20 9.23 9.20 9.21 205 X4 9.27 9.27 9.23 9.22 9.23 9.22 9.23 9.22 9.28 9.22 9.24 206 XS 9.20 9.23 9.28 9.20 9.18 9.20 9.28 9.20 9.18 9.22 207 X6 9.26 9.20 9.28 9.28 9.20 9.28 9.19 9.23 9.22 9.24 9.28 208 209 UCL- 210 LCL, 211 UCL 212 LCL- 213 214 22 10 AFTER you created the control chart limits as shown above, the employees in the process took samples as specified. 215 Remember, the employees always use the control limits they are given by management. Use the control limits from above. 216 Create a Xbar chart and a R chart graph for the data points below by inserting rows and place the charts below the three data points shown. 217 State your conclusions for each of the samples 218 12 13 14 219 X1 9.24 9.23 9.28 220 X2 9.22 9.21 9.26 221 X3 9.24 9.20 9.23 222 9.28 9.23 9.27 223 X 9.28 9.21 9.29 224 X 9.24 9.20 9.29 225 226 R= 227 CLx= 9.28 X4 228 229 230 UCL = LCL," CL 231 UCLR 232 LCLR=

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