Question: Question: Find 3% given that 2x2y3 + 2% = 0. Solution: 2:132 (3y2) 3: + 42: (1,13) + 3x(4y'3) 3: + 3(2y'2) 6222:9232 + 4my3

Question: Find 3% given that 2x2y3 + 2% = 0. Solution:

Question: Find 3% given that 2x2y3 + 2% = 0. Solution: 2:132 (3y2) 3: + 42: (1,13) + 3x(4y'3) 3: + 3(2y'2) 6222:9232 + 4my3 12m(-4y'3) %3y + 3992) 0 Where was the mistake made? a What was the correct step

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