Question: QUESTION From the truth table, simplifying the 4 variable function using Karnaugh Map grouping A B C D Output o o o o 0 0

QUESTION From the truth table, simplifying the 4 variable function using Karnaugh Map grouping A B C D Output o o o o 0 0 0 1 0 0 0 1 0 1 0 0 1 1 0 01001 0 1 0 1 1 01101 01110 1 0001 1 0 0 1 0 1 0 0 0 1 OTTO 1 1 0 0 0 1 1 0 1 0 100 110 OA'CA'D.BD A'B+CD'AD OA'C' A'D' BD A'C' AD.BD AC+A'D+ABD QUESTION 2 Sprint How many gate changes would be required to convert a 16-bit Full Adder to a 16-bit Full subtractior? 18 20 19 O 32 Speints QUESTION What is Right Shift operation >> 2 equivalent to? Multiplying by 2 Dividing by 2 Dividing by 4 Subtracting 4 Adding 4 QUESTION 19 Speints What would be the change in the memory after executing the 6th instruction? 2. X 1. int x, y; 0; 3. y - 0x3CD02700; 4. X = y + 3; int* z = &y + 1; G *Z = y; 6 = "address of * = "dereference" 32-bit example (pointers are 32-bits wide) 0x00001 0x02 03 Ox00 Ox04 03 27 DO 30 Ox08 OxOC Ox10 Ox14 Ox18 0027 DO 30Y Ox1c Ox20 Ox24 N the value stored in z would be the same as x the value stored in z would be the same as y the value stored in address 0x24 will be the same as y the value stored in address Oxic will be the same as y the value stored in address 0x20 will be the same as y pents QUESTION 20 Given that x = 0011 1100, what is the result of x >> 22 0011 1111 0000 1100 0000 1111 1111 1100 00011 1101
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