Question number $28.$

Calculate the indefinite integral: ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(3x^3+6\sqrt[\phantom{2}]{x}+\frac{1}{x^3})dx$

$-\frac{1}{x}+\frac{3}{4}{x}^4+4x^{\frac{3}{2}}+C$

$-\frac{1}{2x^2}+\frac{3}{4}{x}^4-4x^{\frac{3}{2}}+C$

$9x^2+\frac{3}{\sqrt[\phantom{2}]{x}}-\frac{3}{x^4}+C$

$-\frac{1}{2x^2}+x^3-4x^{\frac{3}{2}}+C$

$-\frac{1}{2x^2}+\frac{3}{4}{x}^4+4x^{\frac{3}{2}}+C$

None of the above.