Question: Question PLEASE SOLVE ONLY E , F AND G . THANK YOU. 4 . 1 6 of the textbook. 4 . 1 6 . Consider

Question
PLEASE SOLVE ONLY E, F AND G. THANK YOU.
4.16
of the textbook.
4.16
.
Consider the following chain
-
reaction mechanism for the high
-
temperature formation of
nitric oxide, i
.
e
.
,
the Zeldovich mechanism:
O
+
N
2
-
>
NO
+
N
(2
a
)
N
+
O
2
-
>
NO
+
O
(2
b
)
The reaction rates of Eqs.
(2
a
)
and
(2
b
)
are k
1
f and k
2
f
,
respectively.
A
.
Write out expressions for d
[
NO
]/
dt and d
[
N
]/
dt
.
B
.
Assuming N atoms exist in steady state and that the concentrations of O
,
O
2
,
and N
2
are at their equilibrium values for a specified temperature and composition, simplify your
expression obtained above for d
[
NO
]/
dt for the case of negligible reverse reactions.
(
Answer:
d
[
NO
]/
dt
=
2
k
1
f
[
O
]
eq
[
N
2]
eq
)
C
.
Write out the expression for the steady
-
state N
-
atom concentration used in part B
.
D
.
For the conditions given below and using the assumptions of part B
,
how long does it
take to form
50
ppm
(
mole fraction
\
times
106)
of NO
?
T
=
2100
K
,
\
rho
=
0.167
kg
/
m
3
,
M W
=
28.778
kg
/
kmole
,
\
chi O
,
eq
=
7.6\
times
105
mole fraction,
\
chi O
2
,
eq
=
3.025\
times
103
mole fraction,
\
chi N
2
,
eq
=
0.726
mole fraction, and k
1
f
=
1.82\
times
1014
exp
38370/
T with units of cm
3/
gmol
-
s
.
E
.
Calculate the value of the reverse reaction rate coefficient for the first reaction, i
.
e
.
,
O
+
N
2
NO
+
N
for a temperature of
2100
K
.
F
.
For your computations in part D
,
how good is the assumption that reverse reactions are
negligible? Be quantitative.
G
.
For the conditions of part D
,
determine numerical values for
[
N
]
and
\
chi N
.
Note: k
2
f
=
1.8\
times
1010
T exp
4680/
T with units of cm
3/
gmol
-
s
.
Hint: The answer to part
(
D
)
is: about
37
msec. The answer to part
(
G
)
is: about
9.4\
times
103
ppm

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