Question: Question: The functionD defined by D ( x ) = { x 2 sin ( 1 / x ) 0 if x = 0 (

Question:

The functionD defined by D(x)={x2sin(1/x)0ifx=0(notequalto)ifx=0.

is differentiable at all points. It was stated (without proof) thatD is actually Riemann integrable as well. Explain why, even assuming this, the Fundamental Theorem of Calculus cannot be used to conclude that01D(x)dx=D(1)D(0)

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