QUESTIONS 16 - 28 ONLY

RC Circuits UTD physics Spring 2024 T e [ e ] > Vo Voltage (V) A B A B A B A time () At times slightly before A, the sum of voltages will be V;, [since square wave supplied by the signal generator is V,]. On the other hand, the graph of the capacitor voltage shows that V- is V,, slightly before moment A. However, if we choose a moment after A (for example, the moment half way between A and B), I/ is less than V. 17. How can the sum of voltages be a constant when V Vo Voltage (V) 4 B A B A time (s) The point = 0 is the point on the furthest left that is marked 'A'. At points marked '4', the voltage across the capacitor is as large as it will become. After points '4, the capacitor begins to discharge and the voltage across it drops. The voltage approaches some voltage asymptotically. (It won't necessarily approach zero. In your experimental setup and in the diagram above, the voltage across the capacitor will seem to approach zero but you shouldn't worry unless this voltage is far from zero.) At points marked 'B', the generator changes voltage and again, the voltage across the capacitor approaches a voltage asymptotically. This time the voltage approached is a maximum. (My diagram above makes this maximum voltage look like , but experimentally, the asymptotic approach will be to some smaller voltage.) At the next '4, the generator voltage drops to zero and the cycle repeats. A B