Question: R 1 + R 2 = 2 5 k , W = 5 0 P S f * 1 0 * 5 0 1 2

R1+R2=25k,W=50PSf*10*50
12,500k
+CMR1=0
=25.000lb
(2,5005)+(2,50010)+(2,50015)+(2,50020)+
(2,50025)+(2,50030)+(2,50035)+(2,50040)+
(2,50045)+(2,50050)=R250
R1+R2=25kIps
R2=11.500 or 11.5kIps
R1+11.5k=25k
R1=13.5k
AJ=(10,000)2+(10,000)22
AJ=14,142lb compression
solve for all trusses just like Joint A.
R 1 + R 2 = 2 5 k , W = 5 0 P S f * 1 0 * 5 0 1 2

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