R=((\\\ ho L))/(A)\ A=\\\\pi (0.5d)^(2)

\ find the difference in current

(l)

that a copper wire

(\\\ ho

)

=

(

1.72\\\\times 10^(-8)\\\\Omega *m)

can carry over an alumin

\\\ ho =2.75\\\\times 10^(-8)\\\\Omega *m

) with equal diameters ( ) of

0.62cm

and a length (L) of

10000m

carrying 110 answer to four decimal places.)

R=A(L)A=(0.5d)2 find the difference in current ( ) that a copper wire ( =1.72108m ) can carry over an alumin =2.75108m ) with equal diameters ( ( ) of 0.62cm and a length (L) of 10000m carrying 110 answer to four decimal places.) R=A(L)A=(0.5d)2 find the difference in current ( ) that a copper wire ( =1.72108m ) can carry over an alumin =2.75108m ) with equal diameters ( ( ) of 0.62cm and a length (L) of 10000m carrying 110 answer to four decimal places.)