Question: - r Let f be a Function defued in some neighbourhood of Z 0 with the possible exception of the point z 0 itself. We

-r Let f be a Function defued in some neighbourhood of Z0 with the possible exception of the point z0 itself. We say that the limit of f(z) as z approaches z0 is the Number 0 and rite:limztf(z)=0. Hence |f(z)-0| whenener Use the definition above to prove that 0|z-z0|
limziz2=-1
limzz0f(z)=0
We must show that for a quen >0 there is a pariture number such that:-
z2=f(z)
-1=0
|f(z)-0| whenener |z-z0|
|z-i|
|z2-(-1)|,|z||
|z2+1||||
|(z-i)(z+i)|
- r Let f be a Function defued in some

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!